Build the integrator circuit given and adjust the signal generator to obtain 500 Hz square wave...

 

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Build the integrator circuit given and adjust the signal generator to obtain 500 Hz square wave with 4 Vp-p amplitude. For question b, you can think the input has ofset and for question c you can think the input is a sine wave. a) Derive an expression that gives peak-to-peak output voltage of the integrator in step 2 as a function of square wave amplitude and frequency at the input. b) Derive an expression that gives DC output voltage of the integrator as a function of the input offset. c) Derive an expression that gives peak-to-peak output voltage of the integrator as a function of sine wave amplitude and frequency at the input. Build the integrator circuit given and adjust the signal generator to obtain 500 Hz square wave with 4 Vp-p amplitude. For question b, you can think the input has ofset and for question c you can think the input is a sine wave. a) Derive an expression that gives peak-to-peak output voltage of the integrator in step 2 as a function of square wave amplitude and frequency at the input. b) Derive an expression that gives DC output voltage of the integrator as a function of the input offset. c) Derive an expression that gives peak-to-peak output voltage of the integrator as a function of sine wave amplitude and frequency at the input.