Question: By using Master's Theorem find the time complexity of this algorithm def Max(A) n=len(A) h=n//2 left= A[0:h] right= A[h:n] if n==1: return A[0] else: if

By using Master's Theorem find the time complexity of this algorithm

def Max(A)

n=len(A)

h=n//2

left= A[0:h]

right= A[h:n]

if n==1:

return A[0]

else:

if Max(left) >= Max(right):

return Max(left)

else:

return Max(right)

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