By using Python 3.6: For this problem, you'll be defining a function that calculates the difference between two times of day, where the times of day are represented as strings in the form "h:mm", where h is a number of hours (any number of digits) and mm is the two-digit version of the minutes. So 4:08am would be represented by the string "4:08" and 9:59pm would be represented by "21:59". We want a function that when you input "4:08" and "21:59", will output "17:51".

And finally, you get to put everything together. Define a function time_between() that, given two strings in the form "h:mm" representing two times of day, computes the difference in time between them, returning its answer as a string. So for example, time_between("4:08","21:59") would return the string "17:51" and time_between("101:21","101:29") would return the string "0:08". You're allowed to assume that the second time will always be bigger than the first time.

How can I get to put them together?

This is my code:

def diff_min(mins1,mins2): """return two different times in minutes

number -> number""" return (mins1,mins2)

def time_to_str(time): """return tuple of numbers represents the time

tuple_of_numbers -> str""" return (str(time[0]) + ":" + str(time[1]))

def time_to_minutes(time): """returns hrs and mins to the total number of minutes

tuple_of_numbers -> int""" if time[0] > 0: return time[0]*60+time[1] else: return time[1]

def minutes_to_time(mins): """returns a tuple of two integers given an integer number of minutes

number -> tuple_of_numbers""" return (mins//60,mins%60)

def extract_time(time): """returns a tuple of two integers representing hrs and mins

str -> tuple_of_numbers""" return (int(time[:-3]),int(time[-2:]))