Question: C. [10 pts] Given that arcsin(2x) = 2(2k)! ( k!) 2(2k + 1 ) 2k+1, the series 2(2k)! (k!)2(2k + 1) ( - 3)2k+1 is

C. [10 pts] Given that arcsin(2x) = 2(2k)! ( k!) 2(2k

C. [10 pts] Given that arcsin(2x) = 2(2k)! ( k!) 2(2k + 1 ) 2k+1, the series 2(2k)! (k!)2(2k + 1) ( - 3)2k+1 is the Taylor series centered at: [5 pts] AT=-3 (Br=0 Cr=3 for the function: [5 pts] A arcsin(2x) B arcsin(2x - 3) C arcsin(2x - 6). Explanation

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