c. A 75.0-mL volume of 0.200 M NH 3 (Kb = 1.8 x 10 -5 ) is
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c. A 75.0-mL volume of 0.200 M NH3 (Kb = 1.8 x 10-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 15.0 mL of HNO3 . Express your answer numerically.
d. A 52.0-mL volume of 0.35 M CH3COOH (Ka = 1.8 x 10-5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 19.0 mL of NaOH. Express your answer numerically.
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C Given MHNO3 05 M VHNO3 15 mL MNH3 02 M VNH3 75 mL molHNO3 MHNO3 VHNO3 molHNO3 05 M 15 mL 75 mmol m... View the full answer
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