Question: c ) Consider a byte - addressable main memory consisting of 3 2 Kilobytes and a cache memory has 1 6 blocks with 8 bytes

c) Consider a byte-addressable main memory consisting of 32 Kilobytes and a cache memory has 16 blocks with 8 bytes in each block, direct mapping method is utilized here. i. How many blocks are there in the main memory? ii. How many bits are required to address the main memory? iii. calculate the number of bits of tag, block and offset fields of the memory address?

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