C Language Program Modification

The following program recognizes numbers, words, and individual punctuation marks.

It also accepts free-format input and outputs a single character for each token's type.

For words output, it generates a 'w' and the word, For numbers output 'n' and the number, For punctuation output itself and the EOF should return 'e'.

It uses a global char array lextext[513] to hold the token text.

Sample input:

Voltage = 10 + Current * Resistence; While (n > 5) Do This = That;

Output:

w Voltage = n 10 + W Current * ; w While ( w n > w Do w This = w That ; e

---------------------------------------------------------------------------------------------

#include #include

char lextext[513] = "Voltage = 10 + Current * Resistence;While (n > 5) Do This = That;"; char *pch; int main() { int num, nIndex = 0, k = 0; pch = strtok (lextext," +-*= /;>()"); while ( pch != NULL) { if(pch[k] >= '0' && pch[0] <= '9') { printf("n %s", pch); } k = 0; memset(str,0, 100); if((pch[k] >= 'A') && (pch[k] <= 'Z') || (pch[k] >= 'a') && (pch[k] <= 'z')){ printf("n %s", pch); }

else printf("%s ", pch); if(pch == NULL) { printf("e"); break; } pch = strtok (NULL, " +-*=/ ;>()"); } return 0; }

---------------------------------------------------------------------------------------------

TASK:

YOUR TASK IS TO MODIFY THE PROGRAM SO THAT IT ASKS THE USER TO:

ENTER AN INPUT (currently the string is fixed) Comment each line of the code & indicate the purpose of variables like pch, strtok, memset

Remove Errors in Line 19 ----------> memset(str,0, 100);