C++ Please!!

The following program is the base for the game: tic-tac-toe. The main function and program structure is given, dont modify them. Complete three functions as required. Compile and run this program, and then you can play the game. Have fun!

#include using namespace std;

const int DIM=3; char chessboard[DIM][DIM]; //initChessBoard void initChessBoard(char cb[][DIM])

{

//set all the elements of the ChessBoard to blanks

//Complete this part in the following:

}

//printChessBoard

void printChessBoard(char cb[][DIM])

{

//print all the elements of the chessBoard with each row in one line

//Complete this part in the following:

}

//putChequer

bool putChequer(char cb[][DIM], int i, int j, char x)

{

/* if i and j are not out of bound(that is, i and j are in the range of 0 and DIM-1) and cb[i][j] is not occupied(that is, the value of cb[i][j] is blank), set cb[i][j] to be the value of x and return true. Otherwise, return false.*/

// Complete this part in the following:

}

//judge the state of the game. The player has put x in the position (row, col). // If all the elements in this row are x, x wins // If all the elements in this column are x, x wins. // If x is in the main diagonal, and if all the elements in the main diagonal are x, x wins. // If x is in the opposite diagonal, and if all the elements in the opposite diagonal are x, x wins.

bool state(char cb[][DIM], int row, int col, char x)

{

/* We declare four variables count1, count2, count3, count4 to represent the occurrence number of x in row number row, column number col, in the main diagonal, and in the opposite diagonal. If after calculation, count1, count2, count3 or count4 equals to DIM, return true(that is, x wins). */

int count1=0, count2=0, count3=0, count4=0;

for(int i=0; i

{

// Complete this part in the following:

// if the element in position (row, i) is x, count1 is increased by 1. // if the element in position (i, col) is x, count2 is increased by 1.

/* if x is in the main diagonal, and the element in position (i, i) is x, count3 is increased by 1.*/

/* if x is in the opposite diagonal, and the element in position (i, DIM-1-I) is x, count4 is increased by 1.*/

} return (count1==DIM || count2==DIM || count3==DIM || count4==DIM);

}

int main()

{

int row, col; int blanks=DIM*DIM;

initChessBoard(chessboard);

printChessBoard(chessboard);

char cur='O';

cout<<"Input the position(row col), (-1 -1) for exit; It is the turn of "<

cin>>row>>col;

while(row!=-1 && col!=-1)

{

if(!putChequer(chessboard, row, col, cur))

{

cout<<"Invalid move"<

printChessBoard(chessboard);

}

else

{ --blanks;

printChessBoard(chessboard);

if(state(chessboard, row, col, cur))

{

cout<< cur << " Wins"<

return 0;

}

}; if(blanks==0)

{

cout<< "Ties"<

return 0;

}

if(cur=='X') cur= 'O';

else cur='X';

}

cout<<"Input the position(row col), (-1 -1) for exit; It is the ture of "<

cin>>row>>col;

}

}