C program for converting full string to Number. In the following C program below , there is a function called btoi which takes two arguments, a character array (for a string) and a numeric argument.The first argument is the string representation of a number in a base.

The second argument is the numeric base.The return value for this function is going to by the numeric value for the string representation of the number. If the number is invalid, like with atoi, we're going to return 0. Ignore leading spaces.The function should return once you reach the first invalid character in the string, just like atoi.This function should be able to make use of the digit_btoi function on each character in the string to save you some headaches. That way, you don't need to fumble with ASCII code manipulation in this part of the code. Program : Please write the code where it says Insert your code

int btoi(char buffer[], int base) { /* insert your code here. */

return 0; } void main() {

char buffer[MAX_LENGTH]; char digit;

int number, base;

int argcount;

fprintf(stdout, "Test btoi. Format: "); fprintf(stdout, "> "); argcount = fscanf(stdin, "%s %d[ ]", buffer, &base);

if (argcount < 2) { fprintf(stdout, "Skipping Test btoi. Malformed Input."); fgets(buffer, MAX_LENGTH, stdin); /* Clearing */ } else { fprintf(stdout, "Decimal Number Result: "); fprintf(stdout, "%d ", btoi(buffer, base)); }

Expected Output :

btoi("ZOOT", 36) = 1664957

btoi("HELLO", 36) = 29234652