Question: C. The critical value/values are round to 2 decimal places as needed. D. Since the test statistic _____ the critical value. ____ the null hypothesis.

C. The critical value/values are round to 2 decimal places as needed. D. Since the test statistic _____ the critical value. ____ the null hypothesis. There is ____ evidence that the mean score is lower after the golf lesson. E. Identify the p-value.F. Since the o value ___ the significance level. _____ the null hypothesis. There is ____ evidence that the mean score is lower after the golf lesson.G. Construct a 95% confidence interval to estimate the average reduction in golf scores after the lesson. ULC = LCL= round to two decimal places. H. The lower limit of the interval is ___ zero so there ___ enough evidence to conclude that the average score is low for golfers after the golf lesson when compared to before the golf lesson.I. What assumptions need to be made in order to perform this procedure. The samples are dependent or independent??

C. The critical value/values are round to 2 decimal places as needed.

The accompanying table shows the golf scores of nine golfers before and after a lesson given by a golf professional. Complete parts (a) through (e) below. Click the icon to view the data table. a. Perform a hypothesis test using a = 0.05 to determine if the average score is lower for the golfers after the golf lesson when compared with before the golf lesson. Let uo be the population mean of matched-pair differences for the score before the lesson minus the score after the lesson. State the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Hd = 0 OB. Ho: Hd # 0 Hy : H d # 0 Hy : Hd = 0 & C. Ho: Hd SO OD. Ho: Hd SO Hy : H d > 0 Hy : H d # 0 OE. Ho: Hd

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