Question: Calculate - cell potential - equilibrium constant and - free energy change for Ca (s) + Mn^2+(ag) (1M) -----------> Ca^2+(aq)(1M) + Mn)s) Ca E =

Calculate

- cell potential
- equilibrium constant and
- free energy change for

Ca (s) + Mn^2+(ag) (1M) -----------> Ca^2+(aq)(1M) + Mn)s)
<-----------

given the following E° values

Ca^2+ + 2e^- -------> Ca E° = -2.87 V
Mn^2+ + 2e^- -------> Mn E° = -1.18V


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