Calculate K at 298 K for the following reaction: SrSO4(s)<--> Sr2+(aq) + SO42-(aq) SCIENTIFIC NOTATION PLEASE...thankyou

. Comments : the answer K = 3.48 x 10^-7was wrong,it said HInt:For any state function (G, H, or S) the change in the statefunction, F, for a reaction can be calculated from Delta F rxn=(sideways M)n x delta F (products) minus (sideways M) n x delta F(reactants), when n are the stoichiometric coefficients from thebalanced chemical equation. Use this expression to calculate DeltaG rxn. Use the expression that relates change in fuel energy of areaction, Delta G rxn, to the equilibrium constant K. p.s. (the ^-7power part was correct).

I still get 2 more chances.

comment from chegg:You have not given the standard freeenergies(dG0) of the components. If you have the values simplycalculate dG0 of the reaction, dG0 = ? dG0 value of products -? dG0value of reactants Here it will be, dG0 = (dG0SO42- + dG0Sr2+) -(dG0SrSO4) Then calculate, K according to the equation, dG0 =-RTlnK