This is for C++.

8.5.2: Linked list negative values counting.

Assign negativeCntr with the number of negative values in thelinked list.

#include
#include
using namespace std;

class IntNode {
public:
IntNode(int dataInit = 0, IntNode* nextLoc = nullptr);
void InsertAfter(IntNode* nodePtr);
IntNode* GetNext();
int GetDataVal();
private:
int dataVal;
IntNode* nextNodePtr;
};

// Constructor
IntNode::IntNode(int dataInit, IntNode* nextLoc) {
this->dataVal = dataInit;
this->nextNodePtr = nextLoc;
}

/* Insert node after this node.
* Before: this -- next
* After: this -- node -- next
*/
void IntNode::InsertAfter(IntNode* nodeLoc) {
IntNode* tmpNext = nullptr;

tmpNext = this->nextNodePtr; // Remember next
this->nextNodePtr = nodeLoc; // this -- node -- ?
nodeLoc->nextNodePtr = tmpNext; // this -- node -- next
}

// Grab location pointed by nextNodePtr
IntNode* IntNode::GetNext() {
return this->nextNodePtr;
}

int IntNode::GetDataVal() {
return this->dataVal;
}

int main() {
IntNode* headObj = nullptr; // Create intNode objects
IntNode* currObj = nullptr;
IntNode* lastObj = nullptr;
int i;
int negativeCntr;

negativeCntr = 0;

headObj = new IntNode(-1); // Front of nodes list
lastObj = headObj;

for (i = 0; i < 10; ++i) { // Append 10 rand nums
currObj = new IntNode((rand() % 21) - 10);
lastObj->InsertAfter(currObj); // Append curr
lastObj = currObj; // Curr is the new last item
}

currObj = headObj; // Print the list
while (currObj != nullptr) {
cout << currObj->GetDataVal() << ", ";
currObj = currObj->GetNext();
}
cout << endl;

currObj = headObj; // Count number of negative numbers
while (currObj != nullptr) {

/* Your solution goes here */

currObj = currObj->GetNext();
}
cout << "Number of negatives: " << negativeCntr<< endl;

return 0;
}

Answer rating: 100% (QA)

C program that creates a linked list of integers and count and display the number of negatives in th... View the full answer