Calculate $\underset{x3}{lim}(\frac{\frac{8}{x+1}-\frac{6}{x}}{x-3}).$

$\underset{x3}{lim}(\frac{\frac{8}{x+1}-\frac{6}{x}}{x-3})=0$

$\underset{x3}{lim}(\frac{\frac{8}{x+1}-\frac{6}{x}}{x-3})$ does not exist.

$\underset{x3}{lim}(\frac{\frac{8}{x+1}-\frac{6}{x}}{x-3})=\frac{1}{12}$

$\underset{x3}{lim}(\frac{\frac{8}{x+1}-\frac{6}{x}}{x-3})=\frac{1}{5}$

$\underset{x3}{lim}(\frac{\frac{8}{x+1}-\frac{6}{x}}{x-3})=\frac{1}{6}$