Question: The potential energy, U, of two atoms a distance, r, apart is U=-(A/r^m)+(B/r^n), where m=2 n=10. Given that the atoms form a stable molecule

The potential energy, U, of two atoms a distance, r, apart is U=-(A/r^m)+(B/r^n), where m=2 n=10. Given that the atoms form a stable molecule at a separation of r0= .4nm with a negative energy of -5eV A) Derive the general expression and then calculate A and B. Sketch the resulting force and energy curves. B) Derive the general expressions and then calculate the critical separation at which the molecule breaks (r_max), and the force required to break the molecule (F_max). C) Derive the general expressions and then calculate the stiffness and Elastic Modulus half way before the bond could break. Assume that area of the bond is r0^2

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ANSWER A Deriving the general expression and calculating A and B The potential energy of the two atoms can be written as Ur Arm Brn where m 2n 10 Give... View full answer

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