Calculate the change in entropy of the surroundings (at room temperature) during the process of melting 9 grams of ice. The melting temperature of water is 0˚C and ∆Hfus = 334 J/g or ∆Hfus = 6.02 kJ/mol.

a. 182 J/K

b. 198 J/K

c. –182 J/K

d. 11.0 J/K

e. 10.1 J/K

f. –10.1 J/K

g. –11.0 J/K

h. –198 J/K

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Given H fus 334 Jg So for 9 g of water H fus 334x9 30... View the full answer