Calculate the delta H for the reaction 2Al(s) + 3Cl2 (g) = 2AlCI3 (s) from the following data.

2Al (s) + 6HCl (aq) = 2AlCl3 (aq) + 3H2 (g) with delta H of -1049 kj

HCl (g) = HCl (aq) with delta H of -74.8 kj

H2 (g) + Cl2 (g) = 2HCl (g) with delta H of -1845 kj

AlCl3 (s) = AlCl3 (aq) with delta H of -323 kj