Calculate the distribution storage needed for equalization storage based on the following peak hourly data shown below for the maximum day: $($Complete the table and plot Cumulative data$)$

$\backslash$table$[[$Time$,\backslash$table$[[$Peak$],[$Hourly$],[($L$/$min$)]],\backslash$table$[[$Peak$],[$Hourly$],[$Demand$],[($Lters$)]],\backslash$table$[[$Cumulative$],[$Demand$],[($Liters$)]],$Time,$\backslash$table$[[$Peak$],[$Hourly$],[($L$/$min$)]],\backslash$table$[[$Peak$],[$Hourly$],[$Demand$],[($Liters$)]],\backslash$table$[[$Cumulative$],[$Demand$],[($Liters$)]]],[12am,0,,,12$ pm$,6300,,],[1,2200,,,1,6400,,],[2,2100,,,2,6400,,],[3,2000,,,3,6300,,],[4,2000,,,4,6300,,],[5,2000,,,5,6600,,],[6,2100,,,6,7300,,],[7,3600,,,7,9300,,],[8,5200,,,8,8300,,],[9,5600,,,9,5000,,],[10,5900,,,10,2600,,],[11,6000,,,11,2500,,],[,,,,12,2300,,]]$