Calculate the following binary numbers: $[$show all working$]$

i$.11011010$

$[3$ marks$]$

ii$.1100100$

$[3$ marks$]$

iii. $101-11$

$[3$ marks$]$

iv$.110+100$

$[3$ marks$]$

Design a logic circuit with three inputs whose output will be high only when most inputs are high. $F(ABC)=m_2+m_4+m_5+m_6+m_7$

i$.$ Draw the truth table $($Ti$)$ for the above expression.

$[4$ marks$]$

ii$.$ Write the SOP expression for the output from the above TT$.$

$[1$ mark$]$

iii. Simplify the output $($SOP$)$ by using Karnaugh Map only.

$[5$ marks$]$

iv$.$ Draw the logic circuit for the final expression.

$[5$ marks$].$