Based on a Ke value of 0.210 and the given data table, what are the equilibrium...
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Based on a Ke value of 0.210 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. Consider mixture B, which will cause the net reaction to proceed forward. net> Concentration (M) [XY] [X] + [Y] initial: 0.500 0.100 0.100 change: +x equilibrium: 0.500 – x 0.100 + x 0.100 + x The change in concentration, x, is negative for the reactants because they are consumed and positive for the products because they are produced. Based on a Ke value of 0.210 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. Consider mixture B, which will cause the net reaction to proceed forward. net> Concentration (M) [XY] [X] + [Y] initial: 0.500 0.100 0.100 change: +x equilibrium: 0.500 – x 0.100 + x 0.100 + x The change in concentration, x, is negative for the reactants because they are consumed and positive for the products because they are produced.
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Given Kc 0210 From the given reaction we can write Kc as Kc X Y XY ... View the full answer
Related Book For
Chemistry The Central Science
ISBN: 978-0321696724
12th edition
Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward
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