Question: Calculus 1 Let x(t) = 13 - 412 + t and y(t) = t2 - 6t + 3 At t = 0, a (0) =

Calculus 1

Calculus 1 Let x(t) = 13 - 412 + t and y(t)

Let x(t) = 13 - 412 + t and y(t) = t2 - 6t + 3 At t = 0, a (0) = y(0) = dx t-0 = tangent slope = speed(0)

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