Calculus 3 :

final answer only please, no explanation needed

Section 12.5: Problem 1 (1 point) Evaluate gett'dV where B is the box determined by B 0 = 9 and y = 6.Section 12.5: Problem 7 (1 point) Find the volume of the solid enclosed by the paraboloids 2 = 25 (x2 + y ) and z = 2 - 25 (x] + y?).Section 12.5: Problem 8 (1 point) Express the integral f(z, 3, 2) dV as an iterated integral in six different ways, where E is the solid bounded by z = 0, z = 0,z =y- 7xandy = 14. blew an f(z,y,z)dadyda a = 6= g1(z) =| 92(2) = hi(z, y) = ha(z, y) = f(z,y, =) daddy a =6= gi (y) = 92(y) = hi(z, y) = ka(z, v) =] I lots Jones (z,u, a)dadyda g (2) = =(=)=0 M(y, =) = hz(3,=)= f(z,y, =)didady a =16= gi (y) =92(3) =0 hi(y, =) =h2(3 =)=0 f(z,y, 2)dydade g(z) = 92(2) =[ hi(z, =) = h(z,=) =] f(z, y, 2 )dyded: 9(2) = 92(2)=0 hi(z, =) =hi(z,=)=[Section 12.5: Problem 9 (1 point) Express the integral / f(z, w, =)dV as an iterated integral in six different ways, where E is the solid bounded by z = 0, z = By and I" = 16 -y July) f(z,y, 2)dadydi 91(z) = 92(2) =0 hi(z, y) =h2(z,y) =] Jo. Jazzy f(I,y, = )daddy gi (y) =92(3) = hi(z, y) = he(z, y) =] Jo.() Jaya f(z,y, = )dadyda a= b= g1(=) =| 92(2)=0 hi(y, =) = ha(y,=)=] (ya ) f(z, y, =)daddy a=b= gi (y) =92(3) =[ hi(y, =) =ha(y =)=] (zy, 2 )dydada a =6= g1 (z) = 92(2) = hi(z, =) = h(z, =) =] L.(z,y, z)dydad: a = 16=[ g1 (2) = 92(=) =0 hi(z, =) = hy(z, =) =