Calculus

Problem 3. (1 point) Find the function y that satisfies the following conditions: dy 57 + 8 y(1) = 2. VI y = Problem 4. (1 point) Evaluate the integral by interpreting it in terms of areas. In other words, draw a picture of the region the integral represents, and find the area using high school geometry. J. 162 - 1/d2Problem 5. (1 point) Find the absolute maximum and absolute minimum values of the function f(x) = (x -2)(x -5)3 + 10 on each of the indicated intervals. Enter 'NONE' for any absolute extrema that does not exist. (A) Interval = [1, 4]. Absolute maximum = Absolute minimum = (B) Interval = [1, 8]. Absolute maximum = Absolute minimum = (C) Interval = [4, 9]. Absolute maximum = Absolute minimum = Note: You can earn partial credit on this