Question: call: Im(formula = length ~ log(distance), data = planets. (1) ') Residuals : Min 1Q Median 3Q Max -64. 987 -40.292 3. 106 6 21.221

 call: Im(formula = length ~ log(distance), data = planets. (1) ')Residuals : Min 1Q Median 3Q Max -64. 987 -40.292 3. 106
6 21.221 92.006 Coefficients : Estimate Std. Error t value Pr(>|t|) (Intercept)- 196 . 16 68 . 45 -2.866 0. 02415 log (distance)

call: Im(formula = length ~ log(distance), data = planets. (1) ') Residuals : Min 1Q Median 3Q Max -64. 987 -40.292 3. 106 6 21.221 92.006 Coefficients : Estimate Std. Error t value Pr(>|t|) (Intercept) - 196 . 16 68 . 45 -2.866 0. 02415 log (distance) 42 . 81 11 . 03 3 . 881 0. 00605 Residual standard error: 53.86 on 7 degrees of freedom Multiple R-squared: 0. 6827, Adjusted R-squared: 0. 6373 F-statistic: 15.06 on 1 and 7 DF, p-value: 0. 00604917) (2 points) Write the least-squares regression equation from the model that best straightens the relationship. Don't forget to define the terms in the equation. 18) (2 points) Report the value of R-square for the model that best straightens the relationship. What does this value of R-square mean? 19) (2 points) It has been suggested that the asteroid belt between Mars and Jupiter may be the remnants of a failed planet. Suppose that failed planet was 230 million miles from the sun. Predict its length of year (in earth years) using the best-fitting model. You may do this by hand (showing work) or using R

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