Can someone help me come up with a completely DIFFERENT binomial problem? I put an example of one below. I would greatly appreciate it!!

On this example we will examine the probability a couple who has 8 children has exactly 5 boys.

=binom.dist(5,8,.5,False)

.21875 would be the answer

Next we will look at the probability that they have more than 5 boys.

=1-binom.dist(5,8,.5,True)

.144531 would be the answer

Finally we will look at the probability that they have at most 5 boys.

Assume a .5 chance of having a boy.

=binom.dist(5,8,.5,True)

.855469 would be the answer