Can someone help me with this math problem? I have identified that this problem is related rates. An inverted conical water tank with a height of 12ft and a radius of 6ft is drained through a hole in the vertex at a rate of 2ft^3/s.Volume of cone: v=(1/3)(pi)(r^2)(h)What is the rate of change of the water depth when the water is 3ft? Use exact answer. ??I have identified that 2ft^3/s is dv/dt and I think it's saying I need to find dh/dt. Is this on the right track and if I'm not can someone help me solve this all together ??

10. An inverted conical water tank with a height of 12ft and radius oft is drained through a hole in the vertex at a rate of 2 fts /s. (volume of a cone: v = (7)r2h) du de = 203 + 2 4 dy 6 ft F Z y dy 12 ft dy 2 find Outflow 2 ft /s ah/ de h= 3 (a) What is the rate of change of the water depth when the water is 3ft? Use EXACT