can someone reformat the code below based on the below assignment?

Assignment

Transposition Cipher (encrypt.c): A very simple transposition cipher encrypt(S) can be described by the following rule:

If the length of S is 1 or 2, then encrypt(S) is S.

If S is a string of N characters s₁ s₂...s_N and k=N/2, then enc(S)=encrypt(s_ks_k-1...s₂s₁)+encrypt(s_Ns_N-1...s_k+1) where + indicates string cancatenation. For example, encrypt("OK")="OK" and encrypt("12345678")="34127856".

Write a program to implement this cipher, given an arbitary text string from keyboard, up to 8192 characters. It's better to write a separate encryption function, similar to the following:

char* encrypt(char *string, size_t length) { // you fill this out } 

Input Format: an abitary string (with the length up to 8192 characters). Sample Input: Test early and often! Output Format Line 1: One integer: the toal number of characters in the string. Line 2: The enciphered string. Sample Output:

21 aeyrleT sttf!enn aod

Code

#include

#include

char* encrypt(char *string, size_t length);

void main()

{

char s[8192];char *enc;

printf("enter string: ");

scanf("%s",&s);

enc=encrypt(s,strlen(s));

printf("%s",enc);

}

char* encrypt(char *string, size_t length) {

int n=length;

int k=n/2;k--;

char encstr[length];int i;int c=0;

for(i=k;i>0;i=i-2)

{

encstr[c]=string[i-1];c=c+1;

encstr[c]=string[i];c=c+1;

}

for(i=n-1;i>k+1;i=i-2)

{

encstr[c]=string[i-1];c=c+1;

encstr[c]=string[i];c=c+1;

}

encstr[c]='\0';

char *enc;

enc=encstr;

return enc;

}