Question: can someone solve this Q65. The convolution sum for two causal and finite length sequences {x(n), n = 0, 1, ..., N-1} and {h(n), n

can someone solve this

Q65. The convolution sum for two causal and finite length sequences {x(n), n = 0, 1, ..., N-1} and {h(n), n = 0, 1, ..., L} can be expressed in matrix form for {(n), n = 0, 1, ..., N-1 } as follows: y(0) x(0) x(-1) x(-2) . . . x (-[) h(0) (1) x(1) x(0) x(-1) ... x(-L+1) h(1 ) y(2) x(2) x(1) x(0) . . . x(-L+2) h ( 2) = Ly(N-1)] [x(N-1) x(N-2) x(N -3) .. x(N-L-1) h(L) In a more compact format, we express the convolution matrix as y = x h, where y is an N X 1 vector, x in an N x (L+1) matrix, and h is an (L+1) x 1 vector. a. For the finite length sequences given by x(n) = u(n) - u(n - 3) and h(n) = (0.8)" (u(n) - u(n - 3)), give the matrix equation y = x h and compute y as a multiplication. b. Say that x(n) is periodic with period N and L = N-1. Write the matrix and explain the matrix structure

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