Can someone verify if these answer are correct

Given a normal distribution of raw scores with a mean of 60 and a standard deviation of 8, what proportion of cases fall: (4 points each)

a)between a raw score of 50 and 80?

50-60/8= -1.25 = .3944

80-60/8= 2.5 =.4938

88.82% of scores fall between

b)between a raw score of 48 and 57?

48-60/8 =-1.5 =.4332

57-60/8 =-.375 = .4999

93.31% of scores fall between a raw scorAn