Can you explain in depth how to solve this question

5. [12 points] A portion of the graphs of two functions y = s(t) and y = S(t) are shown below. Suppose that S(t) is the continuous antiderivative of s(t) passing through the point (0, -1). Note that the graphs are linear anywhere they appear to be linear, and that on the intervals (3, 4) and (4, 5), the graph of s(t) is a quarter circle. y = s(t) 3 2 9 1 a. [4 points] Use the portions of the graphs to fill in the exact values -2 1 2 3 5 of S(t) in the table below. t S(t) -2 -2 -1 -3 -1 -2 y = S(t) 3 0 -1 2 2 0 1 3 -2 -1 3 5 1 +1/2 -2 -3