Question: Can you explain the procedure for this result? = n p x = 0 n ( n - 1 ) ! ( x - 1

Can you explain the procedure for this result?=npx=0n(n-1)!(x-1)!(n-1-x+1)!(p)x-1(1-p)n-x
=np(p+1-p)n-x
 Can you explain the procedure for this result?=npx=0n(n-1)!(x-1)!(n-1-x+1)!(p)x-1(1-p)n-x =np(p+1-p)n-x

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