Can you explain where I am evaluating the functions at each critical point and each endpoint

negative or vice versa. SAMPLE QUESTIONS 16) Determine the absolute extrema of the following function over the given interval: f(x) = 2x3 + 3x2 - 12x+ 2, [-4,2] Answer: f(x) = 2x3 + 3x2 - 12x+2 Find the derivative of the function. f(x) = 6x2 + 6x - 12 6(x2 + X - 2)=0 Set the derivative equation to 0 to 6(x + 2)(x - 1)=0 find the critical points. X = -2, 1 f(-4) = -30 f(-2) = 22 f(1) = -5 f(2) = 6 Evaluate the function at each critical point and at each endpoint of the The absolute maximum is 22 and interval. occurs at x = -2. The absolute minimum is -30 and occurs at x = -4