Can you help me answer these problems?

Questions 1-5 are based on the following You randomly clock a sample of 96 vehicles on a freeway and obtain the following vehicle speed data 88 90 83 69 81 89 79 69 81 87 76 69 78 72 82 74 67 85 71 89 93 75 97 81 85 76 72 97 87 67 94 81 78 70 82 97 73 89 70 80 91 88 63 65 81 94 80 85 81 81 77 67 90 101 80 82 93 81 80 89 67 81 95 100 97 88 102 78 84 91 92 84 57 75 88 88 85 86 89 77 75 86 87 95 67 64 99 87 78 70 64 73 81 85 87 82 The variance of the sample is, 100.22 95.45 92.67 89.97 2 The estimated variance of x is, 1.833 1.527 1.273 0.994 You want to build a 95% confidence interval for the population mean vehicle speed. The margin 3 of error (MOE) for the interval is, 3.88 2.77 1.98 1.10 The 95% interval estimate is, 80.7 82.9 79.9 83.8 79.1 84.6 78.0 85.7 You want to build an interval estimate that would capture the population mean mph within +0.5 mph from the sample mean 95% of the time. What is the minimum sample size to yield such an 5 interval? Use the standard deviation from the mph sample for the planning value. 1219 1343 1467 1583Questions 6-10 are related to the following As a statistics course assignment you are to build a 95% confidence interval for the mean monthly rental for two-bedroom apartments in Marion County. A random sample of 88 apartments yields the following data. 990 760 800 750 870 700 750 850 840 880 840 740 870 890 890 980 940 930 960 860 940 1000 670 880 820 820 720 900 1000 960 690 760 920 880 810 810 750 850 890 970 940 890 760 880 920 730 950 900 690 880 950 1130 840 820 850 790 730 860 820 720 780 710 920 930 910 810 950 740 790 840 900 690 840 600 830 940 900 790 910 950 1020 890 890 940 920 950 710 870 The point estimate of the mean monthly rental is, $853.41 $896.08 $914.00 $932.28 The variance of the sample mean is, 97.52 102.40 107.52 112.90 The margin of error for the 95% confidence interval is, $31.43 $25.14 $20.11 $16.09 The upper end of the 95% interval estimate is, $905.08 $884.84 $878.55 $873.52 If you were asked to narrow the 95% margin of error to $10. How many apartments would you 10 need to include in your sample? For planning value use $100. 290 305 345 385Questions 11-14 are related to the following The following is a random sample of full coverage auto insurance policy cost. The data is used to build a 95% interval estimate for the mean cost of full coverage auto insurance policy. 2220 1500 1390 1750 1800 2210 2100 1500 1500 1500 1770 1630 1820 1010 1730 1610 840 1980 2260 1590 1430 1620 1240 1440 1850 1200 1160 1930 1560 1810 1200 1610 1990 1450 1070 1490 1340 1740 1730 2160 1720 1690 1320 2320 2250 1710 1120 2190 1580 1870 1930 1440 1770 1400 1680 1630 1940 1600 1300 1760 1300 1400 1620 1730 1470 2320 1570 1680 1500 1570 11 1360 The point estimate of the mean insurance policy cost is, 1860 a $1,811.92 $1,725.64 $1,643.47 $1,565.21 12 The variance of the sample mean is, a 1446.1 1503.9 103085.1 104115.9 13 The margin or error for the interval estimate is, $95.52 $88.44 $81.89 $75.82 14 The lower end of the 95% interval estimate for the mean speed is, a $1,598.22 b $1,567.65 $1,500.14 $1,443.83