can you help me fill out this information based on what I have done on the chart in the doc: here is the website I got the info from: http://physics.bu.edu/~duffy/vlabs.html Calculations (5 Points Each)

Estimated Potential Energy When Height = 28.0cm = 0.28m P.E=mgh=(2.85)(9.8)(0.28)=7.8J

Work Done by Gravity

W=mg d cos(theta)=(2.85)(9.8)(2.02)(cos(82.03))=7.8J

Length of Slope

Force of Friction

Work Done by Friction

Predicted Final Kinetic Energy

Questions (3 Points Each)

1. Did your initial experiment support the Law of Conservation of Energy? Explain.
2. Did your initial experiment support the Work-Kinetic Energy Theorem? Explain.
3. When friction was applied to the system did the results support the Law of Conservation of Energy? Explain.
4. When friction was applied to the system did the results support the Work-Kinetic Energy Theorem? Explain
5. Do some research. In what situation might the Law of Conservation of Energy not be applicable? Explain.

Conclusion (10 Points)

here is the work I have done: Energy Balance Virtual Lab

Data Table (45 Points) wg= f x d = m x g PE = m x g x h KE = x m x v^2 Mass of object = 2.85 kilograms Y = mgx Plug into graph calculator: Y = 2.85 x 9.81

Height (cm)	Calculated Potential Energy(J)	Actual Potential Energy	Actual Kinetic Energy	Actual Total Energy
0.28meters	7.82 J 2.85 kg x 9.81 m/s^2 x 0.28 = 7.82 7.82 kg x m xm/s^2 Or 7.82 N x M	8 j = 2.85 x 9.81 x h	0	8 J
0.25 meters	7 J 2.85 kg x 9.81 m/s^2 x 0.28 = 6.98	7.2 J	0.8	8 J
0.22 m	6.15 J 2.85 kg x 9.81 x 0.22	6.4 J	1.6	8 J
0.20 m	5.59 J 2.85 kg x 9.81 x 0.2	5.6 J	2.4	8 J
0.175 m	4.89 J 2.85 kg x 9.81 x 0.175	4.8 J	3.2	8 J
0.15 m	4.19 J 2.85 kg x 9.81 x 0.15	4 J	4	8 J
0.12 m	3.35 J 2.85 kg x 9.81 x0.12	3.2 J	4.8	8 J
0.10 m	2.79 J 2.85 kg x 9.81 x 0.10	2.4 J	5.6	8 J
0.07 m	1.95 J 2.85 kg x 9.81 x 0.07	1.6 J	6.4	8 J
0.045 m	1.26 J 2.85 kg x 9.81 x 0.045	0.8 J	7.2	8 J
0.02 m	0.56 J 2.85 kg x 9.81 x 0.02	0 J	8	8 J

Calculations (5 Points Each)

Estimated Potential Energy When Height = 28.0cm = 0.28m P.E=mgh=(2.85)(9.8)(0.28)=7.8J

Work Done by Gravity

W=mg d cos(theta)=(2.85)(9.8)(2.02)(cos(82.03))=7.8J

If you need to see the chart here it is; https://docs.google.com/file/d/1I2WV3FrP_gFLPbX-Anz1CpeuIzLa0m8N/edit?usp=docslist_api&filetype=msword