can you please explain all the steps in the image for this question.

Conjy te beam

Now bedy momet & $c=$ deflection a cin find reactions :$-mQ1=0$ feel beom

Q

$($:$\frac{1}{2}3\frac{36}{I}\frac{2}{3}3+\frac{1}{2}6\frac{36}{I}(3+\frac{1}{3}6)=R_{0}4\}$

$\frac{108}{J}+\frac{540}{EI}=9R_D$

$9R_D=\frac{648}{I}$

$R_D=\frac{72}{EI},R_A=\frac{{}_0}{EI}$

:$.MC=$ deflection $>C$

$R_{D}3-\frac{1}{2}3\frac{18}{I}\frac{1}{3}3$