Can you please write

$1-2$ paragraphs about these parameters for a packed column air stripper and why they are important. Can you also specifiy why you would need each of these to design an air stripper.CALCUIATE MASS TRANSFER RATE

$\frac{a_W}{a_t}=1-e^{-1\mathrm{.}45(\frac{Sc}{}{)}^{0\mathrm{.}75}{N}_{R_e}^{0\mathrm{.}01}{N}_{Fr}^{-0\mathrm{.}05}{N}_{We}0\mathrm{.}2}$

$\frac{1}{K_{LA}}=\frac{1}{H_a{K}_C{a}_w}+\frac{1}{K_L{a}_W}$

$N_{R_e}=(\frac{1}{a_t})\frac{v_L{}_L}{{}_4},$ Reynold's number

$N_{F_r}=a_t\frac{V_L^2}{g_c},$ Froupe number

$N_{we}=(\frac{1}{a_t})\frac{V_L^2{p}_L}{g_{c}5}$ weder number

$N_{Sc}=\frac{{}_L}{{}_L{D}_L},$ Schmidt number

$g_c=9\mathrm{.}807\frac{m}{s^2}$ gravitation constant

CAICUIATE LIQUIO MASS VEIOCITY

$L={}_L\frac{Q_L}{(A)}$

$L=998\mathrm{.}19[\frac{0\mathrm{.}012618}{0\mathrm{.}413419}]$

$=30\mathrm{.}4662\frac{kg}{m^2(s)}$

CALCUIATE REYNOIOS

$N_{R_e}=(\frac{1}{a_t})\frac{V_1{}_L}{{}_L}$

$=(\frac{1}{157})\frac{0\mathrm{.}0305998\mathrm{.}19}{0\mathrm{.}0010042}$

$N_{R_e}=193\mathrm{.}10485$

$N_{R_e}^{0\mathrm{.}1}=1\mathrm{.}693$

$N_{R_e}=(\frac{1}{a_t})\frac{V_1{P}_L}{{}_L}$

$=(\frac{1}{157})\frac{0\mathrm{.}0305998\mathrm{.}19}{0\mathrm{.}0010042}$

$N_{R_e}=193\mathrm{.}10485$

$N_{R_e}^{0\mathrm{.}1}=1\mathrm{.}693$

CAICUIATE FTOUDE $*$

$N_{F_r}=a_t\frac{V_L^2}{g_c}$

$=157\frac{(0\mathrm{.}0305{)}^2}{9\mathrm{.}807}$

$N_{F_r}=0\mathrm{.}0148923$

$N_{Fr}^{-0\mathrm{.}05}=1\mathrm{.}23411$

PARAMETERS

$a_{}=$ wetted surface area of packing

$a_t=$ total surface area of the packing

$k_{La}=$ overall mass transfer rate

$K_L=$ liquid phase mass transfer rate

$k_g=$ gas phase mass transfer rate

WATER PARAMETERS at $20C$

$S=0\mathrm{.}072764\frac{N}{m^2},$

${}_L=0\mathrm{.}0010042k\frac{g}{m}s(viscosity)$

${}_L=998\mathrm{.}20k\frac{g}{m^3}(density)$

PACKING CMARACTERISTICS

$d_p=0\mathrm{.}0508m$

$a_t=157\frac{m^2}{m^3}$

$s_c=0\mathrm{.}033k\frac{g}{s^2}$

$c_t=15$

nominal diameter

total surface area

tension for packing

packing facton

CAICUIATE WETTED AREA

$\frac{a_w}{a_t}=1-e^{-1\mathrm{.}45(\frac{Sc}{}{)}^{0\mathrm{.}75}}{N}_{R_e}^{0\mathrm{.}01}{N}_{Fr}^{-0\mathrm{.}05}{N}_{we}^{0\mathrm{.}2}$

$=1-e^{-1\mathrm{.}45(\frac{0\mathrm{.}033}{0\mathrm{.}0728}{)}^{0\mathrm{.}751\mathrm{.}6931\mathrm{.}234110\mathrm{.}383433}}$

$\frac{a_w}{a_t}=0\mathrm{.}4736=>47\mathrm{.}4\%$

CAiCUIATE WE MED SURFACE AREA

$a_w=47\mathrm{.}36(157)$

$a_w=74\mathrm{.}35\frac{m^2}{m^3}$

CAICUIATE WEbER #

$N_{we}=(\frac{1}{a_t})\frac{V_t^2{P}_L}{g_{c}s}$

$=(\frac{1}{157})\frac{(0\mathrm{.}0305{)}^{2}998\mathrm{.}19}{9\mathrm{.}8070\mathrm{.}072764}$

$N_{we}=0\mathrm{.}008288$

$N_{we}^{0\mathrm{.}2}=0\mathrm{.}383433$