Can you solve the example with fliter area=647 cm^2

This is the solution for filter area=440 cm^2

Can you solve the example with filter area= 647 cm^2 like these steps.

Example Laboratory filtration at constant pressure drop - Slurry: Caco, in H,0 @ T = 25C Filter area = 440 cm 2 647 cm c= 23.5 g/L Evaluate a and Rm as a function of AP Test 1 Test Il Test Test IV Test V Filtrare volume W.L 6 /P 1/ WV 1 / I, / 0.5 50 11.5 44 9.5 198 163 1.5 20 2.5 17.3 41.3 72.0 JOR3 152) 201.7 34.6 41.3 480 54.15 60.84 67.23 68 19.0 34.6 534 760 1020 131.2 163.0 392929299928 13.6 19.0 23.1 26.7 30.4 34,0 37.49 4075 63 140 24.2 37.0 51.7 69.0 126 140 16.13 18.5 20.68 23.0 25 37 27.5 29.78 320 BRB 10,0 11.5 13.2 15.05 17.0 18.7 20.87 22.8 24.67 26.6 28.51 30.42 3.5 4.0 43 88 9.5 10.89 123 13.88 15.0 1685 18.4 19.87 21.46 301 425 $6,5 730 912 1110 1330 156.B 182.5 24,6 34.7 46.1 590 73.6 89.4 107.3 110,0 134.0 1600 5.3 6.0 1 an in lb.': 1, 6.7: 11. 162; 1, 13.2:1, 36.3, V, 19.1. 30 Solution: 70 ap-67 8 8 8 Slope K/2 Intercept 1/4 Pressure drop Ap lb/in. 15 Test /L s s/L R. ft-x10-10 sft /lb x 10 8 40 Sp 162 sp - 282 10 1 II S-343 6.7 16.2 28.2 36.3 49.1 20 965 2,330 4,060 5,230 7,070 13.02 7.24 451 3.82 3.00 10,440 5,800 3,620 3,060 28.21 12.11 9.43 7.49 6.35 800 343 267 212 180 1.98 2.05 2.78 2.84 3.26 1.66 2.23 2.43 2.64 2.80 VO IV V 2,400 0 5 Vown of V. t . 2 V + V 9. x -4 A = 440 cm = 0.474 ft C = 23.5 g/L 1.47 lb/ft3 u = 5.95 * 10 lb/ft.s 1 9. AAPg. jica ' 2.. UR AAP & (44) K a A APg. an R R = 2.56 x 10 AP(19.) sa=8.26x10 APK 93 R. - 2.56x10'AP(1/40) RA1x 10-10 2 21 2.000 6,000 8.000 4.000 Sp. lb/ 4 3 3 X 10-11 NS 2 a = 8.26 x 10 APK 2 4 6 8 10 ap, lb/h? x 10-3