can you solve these 2 please.thansk

EXAMPLE 11 Video Example4 Show that the following limit is true. limx0x6sin(x1)=0 SOLUTION the sine of any number lies between and , we can write the following. sin(x1) Any inequality remains true when multiplied by a positive number. We know that x60 for all x and so, multiplying each side of inequalities by x6, we get x6sin(x1) as illustrated by the figure below. We know the following. limx0x6= and limx0(x5)= Taking f(x)=x6,g(x)=x6sin(1/x), and h(x)=x6 in the Squeeze Theorem, we obtain the following. limx0x6sin(x1)=0 Find limxf(x) if, for all x>1, 4ex16ex17