Question: can you solve this proces modeling and simulation question Department of Chemical and Petroleum Engineering CHME 506-Spring 2023 Assignment # 3 6.1 Increasing Automobile Rear

can you solve this proces modeling and simulation question
can you solve this proces modeling and simulation question Department of Chemical
and Petroleum Engineering CHME 506-Spring 2023 Assignment \# 3 6.1 Increasing Automobile

Department of Chemical and Petroleum Engineering CHME 506-Spring 2023 Assignment \# 3 6.1 Increasing Automobile Rear Windows Temperature A very thin transparent heating element is attached to the inner surface of the rear window to defog an automobile. The glass of an automobile rear window is 0.004m thick and has a thermal conductivity of k=1.4W/(mK). The interior air temperature and convection coefficient are 25C and 10W/m2K, respectively, and the exterior (ambient) air temperature and convection coefficient are 10C and 65W/m2, respectively. Develop an expression for the temperature distribution T(z) in the window. What is the inner surface temperature of the window? Answer: 4.6C 6.2 Heat Transfer in a Wooden Slab The heat flux through a slab made from wood 0.05m thick has been determined to be 40W/m2. The inner surface temperature of the wooden slab is 40C. The thermal conductivity of the wood is k=0.1W/(mK). Develop an expression for the temperature distribution T(z) in the wooden slab. Determine the outer surface temperature of the wooden slab. Answer: 20C Balance Equations in Cartesian Coordinates (xvx+yvy+zvz)=0tCA+(vxxCA+vyyCA+vzzCA)=DAs(x22CA+y22CA+z22CA))+RACptT+Cp(vxxT+vyyT+vzzT)=k(x22T+y22T+z22T)+Htvx+(vxxvx+vyyvz+vzzvz)=(x22vx+y22vx+z22vx)xP+gxtvy+(vxxvy+vyyvz+vzzvy)=(x22vy+y22vy+z22vy)yP+gytvz+(vxxvz+vyyvz+vzzvz)=(x22vz+y22vz+z22vz)zP+g; Balance Equations in Cylindrical Coordinates x=rcos(q),y=rsin(q),z=z(r1rrvr+r1v0+zvr)=0tCA+(v,rCA+v0r1CA+v1zCA)=DA(r1r(rrCA)+r2122CA+z22CA)+RACptT+Cp(vrrT+v0r1T+vzzT)=k(r1r(rrT)+r2122T+z22T)+Htvr+(vrrvr+rv0vrrv02+vzzvr)=(r(r1rvr)+r2122vrr22ve+z22vr)rP+g,tv0+(v+rv0+rv0v0+rvvv0+vtzv0)=(r(r1rv0)+r2122vv+r22vr+z22v0)P+g0tvz+(vrrvz+rv0vt+vzzvz)=(r1r(rrvz)+r2122vt+z22vz)zP+gz

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