CBW converts binary to a word with the algorithm AH:AL where the sign of the 8-bits register AL is extended into the 8-bit register, AH to form a word. What is the value for registers EAX after executing the mnemonic opcode/operand instructions?

MOV EAX, 0 MOV AX, 0ABC3H CBW

	a.	EAX = 0000CCC3
	b.	EAX = 0000ABC3
	c.	EAX = 0000FFC3
	d.	EAX = 000000C3

CWD converts word to a double-word with the algorithm DX:AX where the sign of the 16-bit register AX is extended into the 16-bit register DX. What is the value for registers DX and AX after executing the mnemonic opcode/operand instruction below?

MOV EAX, 0

MOV EDX, 0

MOV AX, 0xCDA5

CWD

	a.	AX= CDA5 DX= FEFF Therefore, its double-word is FEFFCDA5
	b.	AX= ADA5 DX= FFFF Therefore, its double-word is FFFFADA5
	c.	AX= CDA5 DX= EFFF Therefore, its double-word is EFFFCDA5
	d.	AX= CDA5 DX= FFFF Therefore, it double-word is FFFFCDA5

CWDE converts word to double-word extended with the algorithm EAX: AX where the sign of the 16-bit register AX is extended into the 32-bit register EAX. What is the value for registers AX and EAX after executing the mnemonic opcode/operand instruction below?

MOV EAX, 0

MOV AX, 0x429FCDA5

CWDE

	a.	AX= CDA5 EAX=FFFFCDA5
	b.	AX= CDA5 EAX=FFFE000
	c.	AX= CDA5 EAX=EFFFCDA5
	d.	AX= CDA5 EAX=0000CDA5

CDQ converts double-word to quad-word with the algorithm EDX: EAX where the sign of the 32-bit register EAX is extended into the 32-bit register EDX. What is the value for registers EAX and EDX after executing the mnemonic opcode/operand instruction below to generate a quadword?

MOV EAX, 0

MOV EDX, 0

MOV EAX, 0xA29FCDA5

CDQ

	a.	EAX= A29FCDA5 EDX= FFFFFFFF Therefore, its quadword is FFFFFFFFA29FCDA5.
	b.	EAX= A2AFCDA5 EDX= 00000000 Therefore, the its quadword is 00000000A2AFCDA5.
	c.	EAX= A29FCDA5 EDX= 0000FFFF Therefore, its quadword is 0000FFFFA29FCDA5.
	d.	EAX= A29ECDA5 EDX= FFFF0000 Therefore, its quadword is FFF0000A29ECDA5.