Question: char myName[ ] = CS; Given the code above, how many bytes are allocated to myName? O 3 04 1 2. char myName[ ] =

 char myName[ ] = "CS"; Given the code above, how many
bytes are allocated to myName? O 3 04 1 2. char myName[
] = "John"; char myName[5] = "John"; Are the above two statements
equivalent? O True O False int x = 3; int* ptr =

char myName[ ] = "CS"; Given the code above, how many bytes are allocated to myName? O 3 04 1 2. char myName[ ] = "John"; char myName[5] = "John"; Are the above two statements equivalent? O True O False int x = 3; int* ptr = &x; printf("%p" &ptr); Given the code above and assuming that x's address is 0x14. What will be the output of printf function? The address of the pointer (ptr) variable 3 O 14 Ox14 int x = 3; int* ptr = &x; printf("Address of ptr pointer points to is: %p', ptr); Given the code above and assuming that x's address is Ox14. What is the address pointer, ptr, points to? Ox14 O Ox10 O Ox3

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!