Question: char myName[ ] = CS; Given the code above, how many bytes are allocated to myName? O 3 04 1 2. char myName[ ] =

![] = "John"; char myName[5] = "John"; Are the above two statements](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f3cb8ec2a41_39066f3cb8e6014c.jpg)

char myName[ ] = "CS"; Given the code above, how many bytes are allocated to myName? O 3 04 1 2. char myName[ ] = "John"; char myName[5] = "John"; Are the above two statements equivalent? O True O False int x = 3; int* ptr = &x; printf("%p" &ptr); Given the code above and assuming that x's address is 0x14. What will be the output of printf function? The address of the pointer (ptr) variable 3 O 14 Ox14 int x = 3; int* ptr = &x; printf("Address of ptr pointer points to is: %p', ptr); Given the code above and assuming that x's address is Ox14. What is the address pointer, ptr, points to? Ox14 O Ox10 O Ox3
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