Charged nanoparticles in solution are often stabilized by charge repulsion between particles. However, when salt is added, an electric double layer forms, screening the charge from neighboring particles. The length over which charge screening occurs is known as the Debye screening length (1/); for dilute nanoparticle solutions is given by: =(kBTn(zie)2)21 Where e is the charge of an electron, n is the number density of ions (noting that each solution will produce both positive and negative ions), zi is the valence of the ion (1,2,3, etc.), is the solution permittivity and is given by =ro where r is the relative permittivity and o is the permittivity of a vacuum, kB is Boltzmann's constant, and T is the temperature in Kelvin.| (E) Calculate the Debye screening length for a nanoparticle in 0.01M saline ( NaCl in water). You may assume the solution permittivity is the same as that of pure water at 25C. (F) Note that for 1:1 electrolyte at 25C,3.3Co21(Co in mol/L, in nm1). How close is your answer to this value? (G) How would this change for 0.150M Saline (normal saline) at biological conditions of 37 C? (H) Why might this be problematic for NP stabilization