Check the picture provided, i need help breaking the "unbreakable code" in Python Please.The pictures are in order and have been updated. I need to encrypt and decrypt ceasars cipher and figure out why the numbers jump at line 13 and 26... Read the description in pictures provided please. Here's the cipher.txt file: http://tschwarz.mscs.mu.edu/Classes/COSC1010/Projects/Project1/cipher.txt

The middle ages made great progress in many human arts, not excluding the art of cryptography. One of the breakthroughs was an improvement on the Caesar cipher, that was made popular by Vigenre as the "unbreakable code Caesar's Cipher We first take a look at Caesar's code and how to program it in Python. As is traditional, we convert each text into one containing only capital letters. The Caesar cipher uses as a secret a single letter. It conceptually then places two copies of the alphabet over each other, where the "A" is arranged over the secret letter. If the secret letter is N, then A B CDEFQIJ KLMNOPQR STUVWXYZ NOP QRSTUVWXY ZABCDEFGHIJKLM This table defines the encoding. The letters in the cleartext are then substituted by the letters of which they are placed. For example, "GAULASAWHOLEISDIVIDEDINTOTHREEPARTS" becomes "TNHYNFNJUBYRVFQVIVQRQVAGBGUERRCNEGF" There are many ways in which we can implement this transition. One possibility is to use the encoding of ASCl letters. As we have learned, there exist encodings for letters. In Python, we can use the function ord, that gives the encoding for a letter as a decimal integer. Here is the encoding of the capital letters. A B CDEFQIJ KLMNOPQR STUVWXYZ 5 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 The reverse function is chr. You can see this in action with a simple for loop. for letter in "ABCDEFGHJKLnOPQRSTUT#xyz". print (1etter, ord letter)) for num in range(65,91): print (num, chr num) If we want to encode the preceding table, we take the difference between the encoding of a letter and the encoding of A'. For example, if the letter is V', then we obtain rdi, J'}- ord A, 9. This just means that V' is the ninth letter of the alphabet. We add the difference to the code of the key: ord J., - ord A, 1+ord N, ) = 87, which is the encoding of the cipher forJ, namely 'W'. Unfortunately, we need to be careful about going beyond 'Z'. If we want to encode 'T', the same calculation yields