This problem is based on the following cash flows and a MARR of 10% per year....

 

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This problem is based on the following cash flows and a MARR of 10% per year. Z -800,000 -10,000 Alternative First cost, $ Annual cost, $/year Salvage value, $ X -200,000 -60,000 a. $-102,182 b. $-109,484 c. $-121,394 d. $-129,573 -450,000 -30,000 20,000 8000 150,000 Life, years 5 10 In comparing the alternatives by the annual worth method, the annual worth of alternative X is closest to: out of 00 This problem is based on the following cash flows and a MARR of 10% per year. Z -800,000 -10,000 Alternative First cost, $ Annual cost, $/year Salvage value, $ X -200,000 -60,000 a. $-102,182 b. $-109,484 c. $-121,394 d. $-129,573 -450,000 -30,000 20,000 8000 150,000 Life, years 5 10 In comparing the alternatives by the annual worth method, the annual worth of alternative X is closest to: out of 00

Answer rating: 100% (QA)

Answer Geren MARR 10 01 Cashflow diagram of alternative X 120000 5 20000... View the full answer