Regarding bonding: A. A bond is described by the equation ETot -4+ Differentiate and solve for...

 

Transcribed Image Text:

Regarding bonding: A. A bond is described by the equation ETot -4+ Differentiate and solve for the equilibrium bond radius ro in terms of A, B, and n. B. Experiments for a particular material show that the bonding energy is -5.0 eV for a bond length of 0.33 nm and n = 9.0. What are A and B? C. Sketch (or better, use a spreadsheet to plot) the attractive, repulsive, and total energy curves. If the system is at a temperature T = 1000 K, identify on your sketch the region of energy and bond length that the system can access (shade the area). D. What are the minimum and maximum bond lengths at T = 1000 K? E. What happens to the average, minimum and maximum bond lengths if the bonding energy is half of the value in (c), i.e. -2.5 eV? F. Which version has higher coefficient of thermal expansion CTE: the material in (c) or the material in (e)? Explain your answer. Regarding bonding: A. A bond is described by the equation ETot -4+ Differentiate and solve for the equilibrium bond radius ro in terms of A, B, and n. B. Experiments for a particular material show that the bonding energy is -5.0 eV for a bond length of 0.33 nm and n = 9.0. What are A and B? C. Sketch (or better, use a spreadsheet to plot) the attractive, repulsive, and total energy curves. If the system is at a temperature T = 1000 K, identify on your sketch the region of energy and bond length that the system can access (shade the area). D. What are the minimum and maximum bond lengths at T = 1000 K? E. What happens to the average, minimum and maximum bond lengths if the bonding energy is half of the value in (c), i.e. -2.5 eV? F. Which version has higher coefficient of thermal expansion CTE: the material in (c) or the material in (e)? Explain your answer.

Answer rating: 100% (QA)

A To solve for the equilibrium bond radius ro in terms of A B and n we can differentiate the equation for the total energy ETot with respect to r and ... View the full answer