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$2.$ An aluminum block slides along a fixed, smooth bar that goes through the center of the block. A $0\mathrm{.}5$ m long wooden plank hangs from smooth pins in the lower section of the block. Both are moving to the right at a constant speed of $5\frac{m}{s}$ when a breaking force of $F=10N$ to the left is applied.

Find the angular acceleration of the plank the instant that the breaking force is applied. The mass of the plank is $m_p=0\mathrm{.}5kg$ and the block is $m_c=0\mathrm{.}77kg.$ Ignore the small amount of wood removed from the top of the planks to connect to the block.

Solve without instantaneous center of zero velocity

Use this for parts moving away from

$v_C=v_A+r_{\frac{C}{A}}+(v_{\frac{C}{A}}{)}_{xyz}$

$a_C=a_A+{}^{}{r}_{\frac{C}{A}}+(r_{\frac{C}{A}})+2(v_{\frac{C}{A}}{)}_{xyz}+(a_{\frac{C}{A}}{)}_{xyz}$

Use this for parts with fixed points

$v_D={}_{\frac{A}{D}}{r}_{\frac{D}{A}}$

$a_D={}_{AD}{r}_{\frac{D}{A}}-{}_{AD}^2(r_{\frac{D}{A}})$