Question: code class = asciimath > H ( s ) = ( s - 0 . 5 ) / ( ( s + 0 . 1

code class="asciimath">H(s)=(s-0.5)/((s+0.1-5j)(s+0.1+5j))
code class = "asciimath" > H ( s ) = ( s - 0 . 5

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