Question: code class = asciimath > sum _ ( k = 1 ) ^ ( infty ) k ( ( 1 ) / (

code class="asciimath">\sum_(k=1)^(\infty ) k((1)/(2))^(k-1)=
 code class="asciimath">\sum_(k=1)^(\infty ) k((1)/(2))^(k-1)=

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