Question: Combinatorics. n 3. Let an = II (3k 2) for n > 1 and with ao = 1. Prove that for n > 0 k=1

Combinatorics.

Combinatorics. n 3. Let an = II (3k 2) for n > 1

n 3. Let an = II (3k 2) for n > 1 and with ao = 1. Prove that for n > 0 k=1 = 3n diajak i!;!k! i,j,k>0 i+j+k=n Hint: Prove the following identity first: an 3rn

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