Question: Come up with a conditional probability problem with and without replacement. For clarification see the below example: Let's look at a standard deck of 52

Come up with a conditional probability problem with and without replacement.

For clarification see the below example:

Let's look at a standard deck of 52 cards.

What is the probability of getting 2 kings assuming that the first one is not replaced?

4/52 * 3/51 = 1/13*1/17= 1/221

What is the probability of getting 2 kings assuming that the first one is replaced?

4/52 * 4/52 = 1/13 * 1/13 = 1/169

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