Question: Come up with a conditional probability problem with and without replacement. For clarification see the below example: Let's look at a standard deck of 52
Come up with a conditional probability problem with and without replacement.
For clarification see the below example:
Let's look at a standard deck of 52 cards.
What is the probability of getting 2 kings assuming that the first one is not replaced?
4/52 * 3/51 = 1/13*1/17= 1/221
What is the probability of getting 2 kings assuming that the first one is replaced?
4/52 * 4/52 = 1/13 * 1/13 = 1/169
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